The next step is to repeat this process for the other reactant, using different data from a different pair of trials, always making sure that the concentration of only the reactant whose order you are trying to determine is changed from one trial to the other while the concentration of any other reactant remains the same. Once you’ve determined the orders of the reaction with respect to each reactant, you then can write the complete rate law, replacing the
Example:
Given the data below, find the rate law for the following reaction at 300 K.Solution:
First, look for two trials in which the concentrations of all but one of the substances are held constant.a) In Trials 1 and 2, the concentration of A is kept constant, while the concentration of B is doubled. The rate increases by a factor of 8.1/2.0, approximately 4. Write down the rate expression of the two trials.
Trial 1:
Trial 2:
Divide the second equation by the first:
b) In Trials 2 and 3, the concentration of B is kept constant, while the concentration of A is doubled; the rate is increased by a factor of 15.9/8.1, approximately 2. The rate expressions of the two trials are as follows:
Trial 2:
Divide the second equation by the first,
The order of the reaction with respect to A is 1 and with respect to B is 2; the overall reaction order is 1 + 2 = 3.
To calculate k, substitute the values from any one of the above trials into the rate law; e.g.,
2.0 M/sec = k × 1.00 M × (1.00 M)2
k = 2.0 M-2 sec-1Therefore, the rate law is
REACTION ORDERS
We classify chemical reactions on the basis of kinetics into classes of reactions called zero-order, first-order, second-order, mixed-order, or higher-order reactions. We will continue to consider the generic reaction
Zero-Order Reactions
A zero-order reaction is one whose rate of formation of product C is independent of changes in concentrations of any of the reactants, A and B. These reactions have a constant reaction rate equal to the rate coefficient (rate constant) k. The rate law for a zero-order reaction is
rate = k[A]0
[B]0 = kwhere k has units of M·s-1
. (Remember that any number raised to the zero power equals 1.) We will remind you that the rate constant itself is dependent upon temperature; thus, it is possible to change the rate for a zero-order reaction by changing the temperature. The only other way to change the rate of a zero-order reaction is by the addition of a catalyst, which lowers the energy of activation, thereby increasing the value of k.MCAT Expertise
Temperature is the only factor that can change the rate of a zero-order reaction.
First-Order Reactions
A first-order reaction (order = 1) has a rate that is directly proportional to only one reactant, such that doubling the concentration of, say, reactant A results in a doubling of the rate of formation of product C. The rate law for a first-order reaction is
rate = k[A]1
or rate = k[B]1where k has units of s-1
. A classic example of a first-order reaction is the process of radioactive decay. From the rate law, in which the rate of decrease of the amount of a radioactive isotope A is proportional to the amount of A,The concentration of radioactive substance A at any time
[A
where [Ao
] is the initial concentration of A, [ASecond-Order Reactions
A second-order reaction (order = 2) has a rate that is proportional either to the product of the concentrations of two reactants or to the square of the concentration of a single reactant (and zero-order with respect to any other reactant). The following rate laws all reflect second-order reactions:
rate = k[A]1
[B]1 or rate = k[A]0[B]2 = k[B]2 or rate = k[A]2[B]0 = k[A]2where k has units of M-1
sec-1. It is important to recognize that a second-order rate law often suggests a physical collision between two reactant molecules, especially if the rate law is first-order with respect to each of the two reactants.Higher-Order Reactions